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 If you mean G(x) = x² 4x (I'll use a 'y' instead of a 'G(x)') Complete the square y 4 = x² 4x 4 Factor y 4 = (x 2)² Any equation in the form y k = (x h)² is a parabola with its vertex at (h, k); altavistardaltavistard Answer y = (x 2)^2 7 Stepbystep explanation The vertex form of the equation of a parabola (such as we have here) is y = a(xh)^2 k, where (h,k) is the vertex It's safe to assume that the coefficient "a" in y=x^24x3 is 1 The best thing to do now is to complete the squareDivide 1, the coefficient of the x term, by 2 to get \frac {1} {2} Then add the square of \frac {1} {2} to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}x\frac {1} {4}=\frac {y11} {4} Plot A Graph For The Equation Y X 2 4x 1 Y=x^2-4x 1 vertex